二元溶液,T, P一定时,Gibbs—Duhem 方程的正确形式是 ( ).
·X1dlnγ1/dX 1+ X2dlnγ2/dX2 = 0
·X1dlnγ1/dX 2+ X2 dlnγ2/dX1 = 0
·X1dlnγ1/dX 1+ X2dlnγ2/dX1 = 0
·X1dlnγ1/dX 1– X2 dlnγ2/dX1 = 0
出自:佳木斯大学语言治疗学